Mass Transfer B K Dutta Solutions May 2026

Here, we will provide solutions to some of the problems presented in the book “Mass Transfer” by B.K. Dutta.

A mixture of two gases, A and B, is separated by a membrane that is permeable to gas A but not to gas B. The partial pressure of gas A on one side of the membrane is 2 atm, and on the other side, it is 1 atm. If the membrane thickness is 0.1 mm and the permeability of the membrane to gas A is 10^(-6) mol/m²·s·atm, calculate the molar flux of gas A through the membrane. Mass Transfer B K Dutta Solutions

These solutions demonstrate the application of mass transfer principles to practical problems. Here, we will provide solutions to some of

The mass transfer coefficient can be calculated using the following equation: The partial pressure of gas A on one

Assuming \(Re = 100\) and \(Sc = 1\) :

where \(N_A\) is the molar flux of gas A, \(P\) is the permeability of the membrane, \(l\) is the membrane thickness, and \(p_{A1}\) and \(p_{A2}\) are the partial pressures of gas A on either side of the membrane.

A droplet of liquid A is suspended in a gas B. The diameter of the droplet is 1 mm, and the diffusivity of A in B is 10^(-5) m²/s. If the droplet is stationary and the surrounding gas is moving with a velocity of 1 m/s, calculate the mass transfer coefficient.